Complex analysis (identity proof)
$begingroup$
I want to prove $|1-bar zw|=|1-zbar w|$.
The crux being $forall z,win mathbb C: bar zw=zbar w$
Work done so far: I tried breaking down $z$ and $w$ into its components and brute-force my way to validate the equality, but I was not able to prove it.
Any help will be greatly appreciated.
complex-numbers proof-writing
$endgroup$
add a comment |
$begingroup$
I want to prove $|1-bar zw|=|1-zbar w|$.
The crux being $forall z,win mathbb C: bar zw=zbar w$
Work done so far: I tried breaking down $z$ and $w$ into its components and brute-force my way to validate the equality, but I was not able to prove it.
Any help will be greatly appreciated.
complex-numbers proof-writing
$endgroup$
add a comment |
$begingroup$
I want to prove $|1-bar zw|=|1-zbar w|$.
The crux being $forall z,win mathbb C: bar zw=zbar w$
Work done so far: I tried breaking down $z$ and $w$ into its components and brute-force my way to validate the equality, but I was not able to prove it.
Any help will be greatly appreciated.
complex-numbers proof-writing
$endgroup$
I want to prove $|1-bar zw|=|1-zbar w|$.
The crux being $forall z,win mathbb C: bar zw=zbar w$
Work done so far: I tried breaking down $z$ and $w$ into its components and brute-force my way to validate the equality, but I was not able to prove it.
Any help will be greatly appreciated.
complex-numbers proof-writing
complex-numbers proof-writing
edited 1 hour ago
J. W. Tanner
713111
713111
asked 2 hours ago
Bertrand Wittgenstein's GhostBertrand Wittgenstein's Ghost
440115
440115
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add a comment |
1 Answer
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$begingroup$
Hint:
We have $|bar{x}|=|x|$. You just have to identify what should be the $x$ in your question.
Also, in general, $bar{z}w ne zbar{w}$.
$endgroup$
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
Hint:
We have $|bar{x}|=|x|$. You just have to identify what should be the $x$ in your question.
Also, in general, $bar{z}w ne zbar{w}$.
$endgroup$
add a comment |
$begingroup$
Hint:
We have $|bar{x}|=|x|$. You just have to identify what should be the $x$ in your question.
Also, in general, $bar{z}w ne zbar{w}$.
$endgroup$
add a comment |
$begingroup$
Hint:
We have $|bar{x}|=|x|$. You just have to identify what should be the $x$ in your question.
Also, in general, $bar{z}w ne zbar{w}$.
$endgroup$
Hint:
We have $|bar{x}|=|x|$. You just have to identify what should be the $x$ in your question.
Also, in general, $bar{z}w ne zbar{w}$.
answered 2 hours ago
Siong Thye GohSiong Thye Goh
101k1466117
101k1466117
add a comment |
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