base is not a constructor?
1
basePrototype = new base();
// we need to make the options hash a property directly on the new instance
// otherwise we'll modify the options hash on the prototype that we're
// inheriting from
basePrototype.options = $.widget.extend( {}, basePrototype.options );
$.each( prototype, function( prop, value ) {
if ( !$.isFunction( value ) ) {
proxiedPrototype[ prop ] = value;
return;
}
magento2
edited Dec 5 '17 at 10:16
Rakesh Jesadiya
28.7k1571119
asked Dec 5 '17 at 10:11
Suresh RSuresh R
313
add a comment |
1
basePrototype = new base();
// we need to make the options hash a property directly on the new instance
// otherwise we'll modify the options hash on the prototype that we're
// inheriting from
basePrototype.options = $.widget.extend( {}, basePrototype.options );
$.each( prototype, function( prop, value ) {
if ( !$.isFunction( value ) ) {
proxiedPrototype[ prop ] = value;
return;
}
magento2
edited Dec 5 '17 at 10:16
Rakesh Jesadiya
28.7k1571119
asked Dec 5 '17 at 10:11
Suresh RSuresh R
313
it showing error in jquery-ui base is not a constructor
– Suresh R
Dec 5 '17 at 10:12
add a comment |
1
1
1
basePrototype = new base();
// we need to make the options hash a property directly on the new instance
// otherwise we'll modify the options hash on the prototype that we're
// inheriting from
basePrototype.options = $.widget.extend( {}, basePrototype.options );
$.each( prototype, function( prop, value ) {
if ( !$.isFunction( value ) ) {
proxiedPrototype[ prop ] = value;
return;
}
magento2
edited Dec 5 '17 at 10:16
Rakesh Jesadiya
28.7k1571119
asked Dec 5 '17 at 10:11
Suresh RSuresh R
313
basePrototype = new base();
// we need to make the options hash a property directly on the new instance
// otherwise we'll modify the options hash on the prototype that we're
// inheriting from
basePrototype.options = $.widget.extend( {}, basePrototype.options );
$.each( prototype, function( prop, value ) {
if ( !$.isFunction( value ) ) {
proxiedPrototype[ prop ] = value;
return;
}
magento2
magento2
edited Dec 5 '17 at 10:16
Rakesh Jesadiya
28.7k1571119
asked Dec 5 '17 at 10:11
Suresh RSuresh R
313
edited Dec 5 '17 at 10:16
Rakesh Jesadiya
28.7k1571119
asked Dec 5 '17 at 10:11
Suresh RSuresh R
313
edited Dec 5 '17 at 10:16
Rakesh Jesadiya
28.7k1571119
edited Dec 5 '17 at 10:16
Rakesh Jesadiya
28.7k1571119
edited Dec 5 '17 at 10:16
Rakesh Jesadiya
28.7k1571119
28.7k1571119
asked Dec 5 '17 at 10:11
Suresh RSuresh R
313
asked Dec 5 '17 at 10:11
Suresh RSuresh R
313
asked Dec 5 '17 at 10:11
Suresh RSuresh R
313
313
it showing error in jquery-ui base is not a constructor
– Suresh R
Dec 5 '17 at 10:12
add a comment |
it showing error in jquery-ui base is not a constructor
– Suresh R
Dec 5 '17 at 10:12
it showing error in jquery-ui base is not a constructor
– Suresh R
Dec 5 '17 at 10:12
it showing error in jquery-ui base is not a constructor
– Suresh R
Dec 5 '17 at 10:12
add a comment |
1 Answer
1
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oldest
votes
0
If you want to extend a jquery widget, you have to do:
$.widget('namespace.widgetname', base, {
_init: function () {
this._super();
}
}
base should be the jquery-ui widget you want to extend from.
Id don't think that this syntax is correct :
$.widget.extend( {}, basePrototype.options );
answered 5 mins ago
Pierre GauthierPierre Gauthier
183
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
If you want to extend a jquery widget, you have to do:
$.widget('namespace.widgetname', base, {
_init: function () {
this._super();
}
}
base should be the jquery-ui widget you want to extend from.
Id don't think that this syntax is correct :
$.widget.extend( {}, basePrototype.options );
answered 5 mins ago
Pierre GauthierPierre Gauthier
183
add a comment |
0
If you want to extend a jquery widget, you have to do:
$.widget('namespace.widgetname', base, {
_init: function () {
this._super();
}
}
base should be the jquery-ui widget you want to extend from.
Id don't think that this syntax is correct :
$.widget.extend( {}, basePrototype.options );
answered 5 mins ago
Pierre GauthierPierre Gauthier
183
add a comment |
0
0
0
If you want to extend a jquery widget, you have to do:
$.widget('namespace.widgetname', base, {
_init: function () {
this._super();
}
}
base should be the jquery-ui widget you want to extend from.
Id don't think that this syntax is correct :
$.widget.extend( {}, basePrototype.options );
answered 5 mins ago
Pierre GauthierPierre Gauthier
183
If you want to extend a jquery widget, you have to do:
$.widget('namespace.widgetname', base, {
_init: function () {
this._super();
}
}
base should be the jquery-ui widget you want to extend from.
Id don't think that this syntax is correct :
$.widget.extend( {}, basePrototype.options );
answered 5 mins ago
Pierre GauthierPierre Gauthier
183
answered 5 mins ago
Pierre GauthierPierre Gauthier
183
answered 5 mins ago
Pierre GauthierPierre Gauthier
183
answered 5 mins ago
Pierre GauthierPierre Gauthier
183
183
add a comment |
add a comment |
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it showing error in jquery-ui base is not a constructor
– Suresh R
Dec 5 '17 at 10:12