AWK how to count sum
input file (FileInput.txt):
10
20 3
100 5 3
27
this is my awk script:
BEGIN{
while((getline line < "FileInput.txt") > 0) {
}
how can i count sum? I tried sum+=line however it sums only the first column.
awk
edited 6 hours ago
Rui F Ribeiro
39.5k1479132
asked 6 hours ago
user331922user331922
111
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input file (FileInput.txt):
10
20 3
100 5 3
27
this is my awk script:
BEGIN{
while((getline line < "FileInput.txt") > 0) {
}
how can i count sum? I tried sum+=line however it sums only the first column.
awk
edited 6 hours ago
Rui F Ribeiro
39.5k1479132
asked 6 hours ago
user331922user331922
111
New contributor
user331922 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
input file (FileInput.txt):
10
20 3
100 5 3
27
this is my awk script:
BEGIN{
while((getline line < "FileInput.txt") > 0) {
}
how can i count sum? I tried sum+=line however it sums only the first column.
awk
edited 6 hours ago
Rui F Ribeiro
39.5k1479132
asked 6 hours ago
user331922user331922
111
New contributor
user331922 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
input file (FileInput.txt):
10
20 3
100 5 3
27
this is my awk script:
BEGIN{
while((getline line < "FileInput.txt") > 0) {
}
how can i count sum? I tried sum+=line however it sums only the first column.
awk
awk
edited 6 hours ago
Rui F Ribeiro
39.5k1479132
asked 6 hours ago
user331922user331922
111
New contributor
user331922 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 6 hours ago
Rui F Ribeiro
39.5k1479132
asked 6 hours ago
user331922user331922
111
New contributor
user331922 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 6 hours ago
Rui F Ribeiro
39.5k1479132
edited 6 hours ago
Rui F Ribeiro
39.5k1479132
edited 6 hours ago
Rui F Ribeiro
39.5k1479132
39.5k1479132
asked 6 hours ago
user331922user331922
111
New contributor
user331922 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 6 hours ago
user331922user331922
111
asked 6 hours ago
user331922user331922
111
111
New contributor
user331922 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user331922 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
user331922 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Something like can do the work:
awk 'BEGIN {sum=0} {for (i = 1; i <= NF; i++) sum+=$i} END {print sum}' FileInput.txt
answered 6 hours ago
Romeo NinovRomeo Ninov
5,70831928
add a comment |
The issue with your code is twofold:
- It does not actually make use of
awkin the way one usually does. It explicitly loops over the lines of the file in aBEGINblock. This is not the idiomatic way one usually writesawkprograms, which is to supply (optional) patterns or conditions for blocks to be executed for each input record (line). - Since the input consists of records (by default single lines) with more than one number, you would have to treat these records in such a way that the individual numbers are summed up. In other words, you can't add
20 3tosum, but would have to split that up into20and3first.
With GNU awk or mawk, we may set the record separator, RS, to a regular expression that matches any sequence of whitespace characters instead of the default newline. This make awk read the file as a collection of whitespace-separated single field records. Summing these and printing the sum at the end is then trivial:
$ awk -v RS='[[:space:]]+' '{ sum += $1 } END { print sum }' FileInput.txt
168
Altenatively,
$ awk 'BEGIN { RS = "[[:space:]]+" } { sum += $1 } END { print sum }' FileInput.txt
168
Or, you can do some variant on what Romeo Ninov shows, which is to loop over the fields of each line,
$ awk '{ for (i = 1; i <= NF; ++i) sum += $i } END { print sum }' file
168
answered 6 hours ago
KusalanandaKusalananda
124k16234386
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Something like can do the work:
awk 'BEGIN {sum=0} {for (i = 1; i <= NF; i++) sum+=$i} END {print sum}' FileInput.txt
answered 6 hours ago
Romeo NinovRomeo Ninov
5,70831928
add a comment |
Something like can do the work:
awk 'BEGIN {sum=0} {for (i = 1; i <= NF; i++) sum+=$i} END {print sum}' FileInput.txt
answered 6 hours ago
Romeo NinovRomeo Ninov
5,70831928
add a comment |
Something like can do the work:
awk 'BEGIN {sum=0} {for (i = 1; i <= NF; i++) sum+=$i} END {print sum}' FileInput.txt
answered 6 hours ago
Romeo NinovRomeo Ninov
5,70831928
Something like can do the work:
awk 'BEGIN {sum=0} {for (i = 1; i <= NF; i++) sum+=$i} END {print sum}' FileInput.txt
answered 6 hours ago
Romeo NinovRomeo Ninov
5,70831928
answered 6 hours ago
Romeo NinovRomeo Ninov
5,70831928
answered 6 hours ago
Romeo NinovRomeo Ninov
5,70831928
answered 6 hours ago
Romeo NinovRomeo Ninov
5,70831928
5,70831928
add a comment |
add a comment |
The issue with your code is twofold:
- It does not actually make use of
awkin the way one usually does. It explicitly loops over the lines of the file in aBEGINblock. This is not the idiomatic way one usually writesawkprograms, which is to supply (optional) patterns or conditions for blocks to be executed for each input record (line). - Since the input consists of records (by default single lines) with more than one number, you would have to treat these records in such a way that the individual numbers are summed up. In other words, you can't add
20 3tosum, but would have to split that up into20and3first.
With GNU awk or mawk, we may set the record separator, RS, to a regular expression that matches any sequence of whitespace characters instead of the default newline. This make awk read the file as a collection of whitespace-separated single field records. Summing these and printing the sum at the end is then trivial:
$ awk -v RS='[[:space:]]+' '{ sum += $1 } END { print sum }' FileInput.txt
168
Altenatively,
$ awk 'BEGIN { RS = "[[:space:]]+" } { sum += $1 } END { print sum }' FileInput.txt
168
Or, you can do some variant on what Romeo Ninov shows, which is to loop over the fields of each line,
$ awk '{ for (i = 1; i <= NF; ++i) sum += $i } END { print sum }' file
168
answered 6 hours ago
KusalanandaKusalananda
124k16234386
add a comment |
The issue with your code is twofold:
- It does not actually make use of
awkin the way one usually does. It explicitly loops over the lines of the file in aBEGINblock. This is not the idiomatic way one usually writesawkprograms, which is to supply (optional) patterns or conditions for blocks to be executed for each input record (line). - Since the input consists of records (by default single lines) with more than one number, you would have to treat these records in such a way that the individual numbers are summed up. In other words, you can't add
20 3tosum, but would have to split that up into20and3first.
With GNU awk or mawk, we may set the record separator, RS, to a regular expression that matches any sequence of whitespace characters instead of the default newline. This make awk read the file as a collection of whitespace-separated single field records. Summing these and printing the sum at the end is then trivial:
$ awk -v RS='[[:space:]]+' '{ sum += $1 } END { print sum }' FileInput.txt
168
Altenatively,
$ awk 'BEGIN { RS = "[[:space:]]+" } { sum += $1 } END { print sum }' FileInput.txt
168
Or, you can do some variant on what Romeo Ninov shows, which is to loop over the fields of each line,
$ awk '{ for (i = 1; i <= NF; ++i) sum += $i } END { print sum }' file
168
answered 6 hours ago
KusalanandaKusalananda
124k16234386
add a comment |
The issue with your code is twofold:
- It does not actually make use of
awkin the way one usually does. It explicitly loops over the lines of the file in aBEGINblock. This is not the idiomatic way one usually writesawkprograms, which is to supply (optional) patterns or conditions for blocks to be executed for each input record (line). - Since the input consists of records (by default single lines) with more than one number, you would have to treat these records in such a way that the individual numbers are summed up. In other words, you can't add
20 3tosum, but would have to split that up into20and3first.
With GNU awk or mawk, we may set the record separator, RS, to a regular expression that matches any sequence of whitespace characters instead of the default newline. This make awk read the file as a collection of whitespace-separated single field records. Summing these and printing the sum at the end is then trivial:
$ awk -v RS='[[:space:]]+' '{ sum += $1 } END { print sum }' FileInput.txt
168
Altenatively,
$ awk 'BEGIN { RS = "[[:space:]]+" } { sum += $1 } END { print sum }' FileInput.txt
168
Or, you can do some variant on what Romeo Ninov shows, which is to loop over the fields of each line,
$ awk '{ for (i = 1; i <= NF; ++i) sum += $i } END { print sum }' file
168
answered 6 hours ago
KusalanandaKusalananda
124k16234386
The issue with your code is twofold:
- It does not actually make use of
awkin the way one usually does. It explicitly loops over the lines of the file in aBEGINblock. This is not the idiomatic way one usually writesawkprograms, which is to supply (optional) patterns or conditions for blocks to be executed for each input record (line). - Since the input consists of records (by default single lines) with more than one number, you would have to treat these records in such a way that the individual numbers are summed up. In other words, you can't add
20 3tosum, but would have to split that up into20and3first.
With GNU awk or mawk, we may set the record separator, RS, to a regular expression that matches any sequence of whitespace characters instead of the default newline. This make awk read the file as a collection of whitespace-separated single field records. Summing these and printing the sum at the end is then trivial:
$ awk -v RS='[[:space:]]+' '{ sum += $1 } END { print sum }' FileInput.txt
168
Altenatively,
$ awk 'BEGIN { RS = "[[:space:]]+" } { sum += $1 } END { print sum }' FileInput.txt
168
Or, you can do some variant on what Romeo Ninov shows, which is to loop over the fields of each line,
$ awk '{ for (i = 1; i <= NF; ++i) sum += $i } END { print sum }' file
168
answered 6 hours ago
KusalanandaKusalananda
124k16234386
edited 7 mins ago
answered 6 hours ago
KusalanandaKusalananda
124k16234386
answered 6 hours ago
KusalanandaKusalananda
124k16234386
answered 6 hours ago
KusalanandaKusalananda
124k16234386
124k16234386
add a comment |
add a comment |
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