pandas filling nans by mean of before and after non-nan values
6
I would like to fill df's nan with an average of adjacent elements.
Consider a dataframe:
df = pd.DataFrame({'val': [1,np.nan, 4, 5, np.nan, 10, 1,2,5, np.nan, np.nan, 9]})
val
0 1.0
1 NaN
2 4.0
3 5.0
4 NaN
5 10.0
6 1.0
7 2.0
8 5.0
9 NaN
10 NaN
11 9.0
My desired output is:
val
0 1.0
1 2.5
2 4.0
3 5.0
4 7.5
5 10.0
6 1.0
7 2.0
8 5.0
9 7.0 <<< deadend
10 7.0 <<< deadend
11 9.0
I've looked into other solutions such as Fill cell containing NaN with average of value before and after, but this won't work in case of two or more consecutive np.nans.
Any help is greatly appreciated!
python pandas
asked 19 mins ago
ChrisChris
1,181213
add a comment |
6
I would like to fill df's nan with an average of adjacent elements.
Consider a dataframe:
df = pd.DataFrame({'val': [1,np.nan, 4, 5, np.nan, 10, 1,2,5, np.nan, np.nan, 9]})
val
0 1.0
1 NaN
2 4.0
3 5.0
4 NaN
5 10.0
6 1.0
7 2.0
8 5.0
9 NaN
10 NaN
11 9.0
My desired output is:
val
0 1.0
1 2.5
2 4.0
3 5.0
4 7.5
5 10.0
6 1.0
7 2.0
8 5.0
9 7.0 <<< deadend
10 7.0 <<< deadend
11 9.0
I've looked into other solutions such as Fill cell containing NaN with average of value before and after, but this won't work in case of two or more consecutive np.nans.
Any help is greatly appreciated!
python pandas
asked 19 mins ago
ChrisChris
1,181213
add a comment |
6
6
6
I would like to fill df's nan with an average of adjacent elements.
Consider a dataframe:
df = pd.DataFrame({'val': [1,np.nan, 4, 5, np.nan, 10, 1,2,5, np.nan, np.nan, 9]})
val
0 1.0
1 NaN
2 4.0
3 5.0
4 NaN
5 10.0
6 1.0
7 2.0
8 5.0
9 NaN
10 NaN
11 9.0
My desired output is:
val
0 1.0
1 2.5
2 4.0
3 5.0
4 7.5
5 10.0
6 1.0
7 2.0
8 5.0
9 7.0 <<< deadend
10 7.0 <<< deadend
11 9.0
I've looked into other solutions such as Fill cell containing NaN with average of value before and after, but this won't work in case of two or more consecutive np.nans.
Any help is greatly appreciated!
python pandas
asked 19 mins ago
ChrisChris
1,181213
I would like to fill df's nan with an average of adjacent elements.
Consider a dataframe:
df = pd.DataFrame({'val': [1,np.nan, 4, 5, np.nan, 10, 1,2,5, np.nan, np.nan, 9]})
val
0 1.0
1 NaN
2 4.0
3 5.0
4 NaN
5 10.0
6 1.0
7 2.0
8 5.0
9 NaN
10 NaN
11 9.0
My desired output is:
val
0 1.0
1 2.5
2 4.0
3 5.0
4 7.5
5 10.0
6 1.0
7 2.0
8 5.0
9 7.0 <<< deadend
10 7.0 <<< deadend
11 9.0
I've looked into other solutions such as Fill cell containing NaN with average of value before and after, but this won't work in case of two or more consecutive np.nans.
Any help is greatly appreciated!
python pandas
python pandas
asked 19 mins ago
ChrisChris
1,181213
asked 19 mins ago
ChrisChris
1,181213
asked 19 mins ago
ChrisChris
1,181213
asked 19 mins ago
ChrisChris
1,181213
asked 19 mins ago
ChrisChris
1,181213
1,181213
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
9
Use ffill and bfill and divide by 2:
df = (df.ffill()+df.bfill())/2
print(df)
val
0 1.0
1 2.5
2 4.0
3 5.0
4 7.5
5 10.0
6 1.0
7 2.0
8 5.0
9 7.0
10 7.0
11 9.0
answered 13 mins ago
Sandeep KadapaSandeep Kadapa
6,813629
3
That is just brilliant. Thanks a ton :)
– Chris
11 mins ago
@Chris Glad to help.
– Sandeep Kadapa
6 mins ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
9
Use ffill and bfill and divide by 2:
df = (df.ffill()+df.bfill())/2
print(df)
val
0 1.0
1 2.5
2 4.0
3 5.0
4 7.5
5 10.0
6 1.0
7 2.0
8 5.0
9 7.0
10 7.0
11 9.0
answered 13 mins ago
Sandeep KadapaSandeep Kadapa
6,813629
3
That is just brilliant. Thanks a ton :)
– Chris
11 mins ago
@Chris Glad to help.
– Sandeep Kadapa
6 mins ago
add a comment |
9
Use ffill and bfill and divide by 2:
df = (df.ffill()+df.bfill())/2
print(df)
val
0 1.0
1 2.5
2 4.0
3 5.0
4 7.5
5 10.0
6 1.0
7 2.0
8 5.0
9 7.0
10 7.0
11 9.0
answered 13 mins ago
Sandeep KadapaSandeep Kadapa
6,813629
3
That is just brilliant. Thanks a ton :)
– Chris
11 mins ago
@Chris Glad to help.
– Sandeep Kadapa
6 mins ago
add a comment |
9
9
9
Use ffill and bfill and divide by 2:
df = (df.ffill()+df.bfill())/2
print(df)
val
0 1.0
1 2.5
2 4.0
3 5.0
4 7.5
5 10.0
6 1.0
7 2.0
8 5.0
9 7.0
10 7.0
11 9.0
answered 13 mins ago
Sandeep KadapaSandeep Kadapa
6,813629
Use ffill and bfill and divide by 2:
df = (df.ffill()+df.bfill())/2
print(df)
val
0 1.0
1 2.5
2 4.0
3 5.0
4 7.5
5 10.0
6 1.0
7 2.0
8 5.0
9 7.0
10 7.0
11 9.0
answered 13 mins ago
Sandeep KadapaSandeep Kadapa
6,813629
answered 13 mins ago
Sandeep KadapaSandeep Kadapa
6,813629
answered 13 mins ago
Sandeep KadapaSandeep Kadapa
6,813629
answered 13 mins ago
Sandeep KadapaSandeep Kadapa
6,813629
6,813629
3
That is just brilliant. Thanks a ton :)
– Chris
11 mins ago
@Chris Glad to help.
– Sandeep Kadapa
6 mins ago
add a comment |
3
That is just brilliant. Thanks a ton :)
– Chris
11 mins ago
@Chris Glad to help.
– Sandeep Kadapa
6 mins ago
3
3
That is just brilliant. Thanks a ton :)
– Chris
11 mins ago
That is just brilliant. Thanks a ton :)
– Chris
11 mins ago
@Chris Glad to help.
– Sandeep Kadapa
6 mins ago
@Chris Glad to help.
– Sandeep Kadapa
6 mins ago
add a comment |
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