Why will Wolfram CountryData not give population data after 2014 (e.g. for the US)?
$begingroup$
CountryData[ "UnitedStates", {"Population", 2014} ]
322 422 965 people
CountryData[ "UnitedStates", {"Population", 2015} ]
Missing[ "NotAvailable" ]
How can I update it?
I am new to Mathematica.
curated-data
New contributor
$endgroup$
add a comment |
$begingroup$
CountryData[ "UnitedStates", {"Population", 2014} ]
322 422 965 people
CountryData[ "UnitedStates", {"Population", 2015} ]
Missing[ "NotAvailable" ]
How can I update it?
I am new to Mathematica.
curated-data
New contributor
$endgroup$
$begingroup$
Both statistics and its implementation in Mathematica are slow. Lags usually equal few years. WolframAlpha in my Mma through ==Population of United States in 2015 answers 320 million people (2015 estimate).
$endgroup$
– user64494
3 hours ago
1
$begingroup$
Also WA in my Mma answers 327 million people (world rank: 3^(rd)) (2018 estimate)
$endgroup$
– user64494
2 hours ago
$begingroup$
@user64494 That is interesting,WolframAlpha[ "Population of the United States"]
for me returns 324 million people (2017 estimate). Seems like there are different data bases queried?
$endgroup$
– gwr
2 hours ago
$begingroup$
@gwr: Your question should be addressed to Wolfram developers, not to me. Try WolframAlpha["Population of the United States in 2018"]. Good luck!
$endgroup$
– user64494
2 hours ago
$begingroup$
@user64494 But you indeed have given the answer! Specifically asking for the population in 2018 will give the value you have given. It simply will not appear just asking for population for some reason. :)
$endgroup$
– gwr
2 hours ago
add a comment |
$begingroup$
CountryData[ "UnitedStates", {"Population", 2014} ]
322 422 965 people
CountryData[ "UnitedStates", {"Population", 2015} ]
Missing[ "NotAvailable" ]
How can I update it?
I am new to Mathematica.
curated-data
New contributor
$endgroup$
CountryData[ "UnitedStates", {"Population", 2014} ]
322 422 965 people
CountryData[ "UnitedStates", {"Population", 2015} ]
Missing[ "NotAvailable" ]
How can I update it?
I am new to Mathematica.
curated-data
curated-data
New contributor
New contributor
edited 2 hours ago
gwr
7,70322558
7,70322558
New contributor
asked 3 hours ago
user10311334user10311334
211
211
New contributor
New contributor
$begingroup$
Both statistics and its implementation in Mathematica are slow. Lags usually equal few years. WolframAlpha in my Mma through ==Population of United States in 2015 answers 320 million people (2015 estimate).
$endgroup$
– user64494
3 hours ago
1
$begingroup$
Also WA in my Mma answers 327 million people (world rank: 3^(rd)) (2018 estimate)
$endgroup$
– user64494
2 hours ago
$begingroup$
@user64494 That is interesting,WolframAlpha[ "Population of the United States"]
for me returns 324 million people (2017 estimate). Seems like there are different data bases queried?
$endgroup$
– gwr
2 hours ago
$begingroup$
@gwr: Your question should be addressed to Wolfram developers, not to me. Try WolframAlpha["Population of the United States in 2018"]. Good luck!
$endgroup$
– user64494
2 hours ago
$begingroup$
@user64494 But you indeed have given the answer! Specifically asking for the population in 2018 will give the value you have given. It simply will not appear just asking for population for some reason. :)
$endgroup$
– gwr
2 hours ago
add a comment |
$begingroup$
Both statistics and its implementation in Mathematica are slow. Lags usually equal few years. WolframAlpha in my Mma through ==Population of United States in 2015 answers 320 million people (2015 estimate).
$endgroup$
– user64494
3 hours ago
1
$begingroup$
Also WA in my Mma answers 327 million people (world rank: 3^(rd)) (2018 estimate)
$endgroup$
– user64494
2 hours ago
$begingroup$
@user64494 That is interesting,WolframAlpha[ "Population of the United States"]
for me returns 324 million people (2017 estimate). Seems like there are different data bases queried?
$endgroup$
– gwr
2 hours ago
$begingroup$
@gwr: Your question should be addressed to Wolfram developers, not to me. Try WolframAlpha["Population of the United States in 2018"]. Good luck!
$endgroup$
– user64494
2 hours ago
$begingroup$
@user64494 But you indeed have given the answer! Specifically asking for the population in 2018 will give the value you have given. It simply will not appear just asking for population for some reason. :)
$endgroup$
– gwr
2 hours ago
$begingroup$
Both statistics and its implementation in Mathematica are slow. Lags usually equal few years. WolframAlpha in my Mma through ==Population of United States in 2015 answers 320 million people (2015 estimate).
$endgroup$
– user64494
3 hours ago
$begingroup$
Both statistics and its implementation in Mathematica are slow. Lags usually equal few years. WolframAlpha in my Mma through ==Population of United States in 2015 answers 320 million people (2015 estimate).
$endgroup$
– user64494
3 hours ago
1
1
$begingroup$
Also WA in my Mma answers 327 million people (world rank: 3^(rd)) (2018 estimate)
$endgroup$
– user64494
2 hours ago
$begingroup$
Also WA in my Mma answers 327 million people (world rank: 3^(rd)) (2018 estimate)
$endgroup$
– user64494
2 hours ago
$begingroup$
@user64494 That is interesting,
WolframAlpha[ "Population of the United States"]
for me returns 324 million people (2017 estimate). Seems like there are different data bases queried?$endgroup$
– gwr
2 hours ago
$begingroup$
@user64494 That is interesting,
WolframAlpha[ "Population of the United States"]
for me returns 324 million people (2017 estimate). Seems like there are different data bases queried?$endgroup$
– gwr
2 hours ago
$begingroup$
@gwr: Your question should be addressed to Wolfram developers, not to me. Try WolframAlpha["Population of the United States in 2018"]. Good luck!
$endgroup$
– user64494
2 hours ago
$begingroup$
@gwr: Your question should be addressed to Wolfram developers, not to me. Try WolframAlpha["Population of the United States in 2018"]. Good luck!
$endgroup$
– user64494
2 hours ago
$begingroup$
@user64494 But you indeed have given the answer! Specifically asking for the population in 2018 will give the value you have given. It simply will not appear just asking for population for some reason. :)
$endgroup$
– gwr
2 hours ago
$begingroup$
@user64494 But you indeed have given the answer! Specifically asking for the population in 2018 will give the value you have given. It simply will not appear just asking for population for some reason. :)
$endgroup$
– gwr
2 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
CountryData
does appear to be out of date, and that is a shame. Many of the XXXData functions now act as wrappers to call EntityValue
. Run TracePrint[PlanetData["Venus", "AngularDiameterFromEarth"],_EntityValue]
to see that this is true.
But CountryData
has not been updated to work this way. So we can call EntityValue
directly for the data. To find out what the right syntax would be I will use Ctrl=:
becomes
which is a formatted form of
Entity["Country", "UnitedStates"][
EntityProperty["Country", "Population", {"Date" -> DateObject[{1978}]}]
]
I can query for a date range as well. Using Ctrl= on "US population 2000 through 2018"
returns this input expression:
Entity["Country", "UnitedStates"][
EntityProperty["Country",
"Population",
{"Date" -> Interval[{DateObject[{2000}], DateObject @ {2018}}]}
]
]
which returns a TimeSeries
object suitable for further computation or visualization.
$endgroup$
add a comment |
$begingroup$
You should report to WRI. As a workaround you may use the entity functions instead; it is a bit verbose.
First you can get a list of qualifier values of an EntityProperty
by
EntityValue[EntityProperty["Country", "Population"], "QualifierValues"]
{Age->{Adult,MiddleAge,PreSchool,SchoolAge,Senior,Young,YoungAdult},
CitizenshipStatus->{BornInPuertoRico,BornInUS,BornToAmericanParents,NaturalizedCitizen,NotCitizen,TotalCitizens},
Date->{},
Gender->{Female,Male},
HispanicOrigin->{Argentinean,Bolivian,CentralAmerican,Chilean,Colombian,CostaRican,Cuban,Dominican,Ecuadorian,Guatemalan,Hispanic,HispanicOrLatinoAllOther,Honduran,Mexican,Nicaraguan,NotHispanic,OtherCentralAmerican,OtherHispanicOrLatino,OtherSouthAmerican,Panamanian,Paraguayan,Peruvian,PuertoRican,Salvadoran,SouthAmerican,Spaniard,Spanish,SpanishAmerican,Uruguayan,Venezuelan},
MarginOfError->{MarginOfError,StandardError},
Percent->{Main},
Race->{AmericanIndian,Asian,Black,NativeHawaiian,Other,TwoOrMore,White,{All,Hispanic}},
TwoOrMore->{ThreeOrMore,TwoIncludingOther},
UrbanRural->{Rural,Urban}}
"Date"
is a qualifier. This post gives details on how to specify a "Date"
qualifier (156014); an area where the docs can improve.
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country", "Population", {"Date" -> DateObject[{2015}]}]
]
319,929,162 people
However, you do have a bit more flexibility with this syntax.
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country",
"Population", {"Date" -> Interval[{DateObject[{2015}], DateObject[{2019}]}]}]
]
and
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country", "Population", {"Date" -> All}]
]
Hope this helps.
$endgroup$
add a comment |
Your Answer
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2 Answers
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2 Answers
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$begingroup$
CountryData
does appear to be out of date, and that is a shame. Many of the XXXData functions now act as wrappers to call EntityValue
. Run TracePrint[PlanetData["Venus", "AngularDiameterFromEarth"],_EntityValue]
to see that this is true.
But CountryData
has not been updated to work this way. So we can call EntityValue
directly for the data. To find out what the right syntax would be I will use Ctrl=:
becomes
which is a formatted form of
Entity["Country", "UnitedStates"][
EntityProperty["Country", "Population", {"Date" -> DateObject[{1978}]}]
]
I can query for a date range as well. Using Ctrl= on "US population 2000 through 2018"
returns this input expression:
Entity["Country", "UnitedStates"][
EntityProperty["Country",
"Population",
{"Date" -> Interval[{DateObject[{2000}], DateObject @ {2018}}]}
]
]
which returns a TimeSeries
object suitable for further computation or visualization.
$endgroup$
add a comment |
$begingroup$
CountryData
does appear to be out of date, and that is a shame. Many of the XXXData functions now act as wrappers to call EntityValue
. Run TracePrint[PlanetData["Venus", "AngularDiameterFromEarth"],_EntityValue]
to see that this is true.
But CountryData
has not been updated to work this way. So we can call EntityValue
directly for the data. To find out what the right syntax would be I will use Ctrl=:
becomes
which is a formatted form of
Entity["Country", "UnitedStates"][
EntityProperty["Country", "Population", {"Date" -> DateObject[{1978}]}]
]
I can query for a date range as well. Using Ctrl= on "US population 2000 through 2018"
returns this input expression:
Entity["Country", "UnitedStates"][
EntityProperty["Country",
"Population",
{"Date" -> Interval[{DateObject[{2000}], DateObject @ {2018}}]}
]
]
which returns a TimeSeries
object suitable for further computation or visualization.
$endgroup$
add a comment |
$begingroup$
CountryData
does appear to be out of date, and that is a shame. Many of the XXXData functions now act as wrappers to call EntityValue
. Run TracePrint[PlanetData["Venus", "AngularDiameterFromEarth"],_EntityValue]
to see that this is true.
But CountryData
has not been updated to work this way. So we can call EntityValue
directly for the data. To find out what the right syntax would be I will use Ctrl=:
becomes
which is a formatted form of
Entity["Country", "UnitedStates"][
EntityProperty["Country", "Population", {"Date" -> DateObject[{1978}]}]
]
I can query for a date range as well. Using Ctrl= on "US population 2000 through 2018"
returns this input expression:
Entity["Country", "UnitedStates"][
EntityProperty["Country",
"Population",
{"Date" -> Interval[{DateObject[{2000}], DateObject @ {2018}}]}
]
]
which returns a TimeSeries
object suitable for further computation or visualization.
$endgroup$
CountryData
does appear to be out of date, and that is a shame. Many of the XXXData functions now act as wrappers to call EntityValue
. Run TracePrint[PlanetData["Venus", "AngularDiameterFromEarth"],_EntityValue]
to see that this is true.
But CountryData
has not been updated to work this way. So we can call EntityValue
directly for the data. To find out what the right syntax would be I will use Ctrl=:
becomes
which is a formatted form of
Entity["Country", "UnitedStates"][
EntityProperty["Country", "Population", {"Date" -> DateObject[{1978}]}]
]
I can query for a date range as well. Using Ctrl= on "US population 2000 through 2018"
returns this input expression:
Entity["Country", "UnitedStates"][
EntityProperty["Country",
"Population",
{"Date" -> Interval[{DateObject[{2000}], DateObject @ {2018}}]}
]
]
which returns a TimeSeries
object suitable for further computation or visualization.
answered 2 hours ago
Jason B.Jason B.
48k388187
48k388187
add a comment |
add a comment |
$begingroup$
You should report to WRI. As a workaround you may use the entity functions instead; it is a bit verbose.
First you can get a list of qualifier values of an EntityProperty
by
EntityValue[EntityProperty["Country", "Population"], "QualifierValues"]
{Age->{Adult,MiddleAge,PreSchool,SchoolAge,Senior,Young,YoungAdult},
CitizenshipStatus->{BornInPuertoRico,BornInUS,BornToAmericanParents,NaturalizedCitizen,NotCitizen,TotalCitizens},
Date->{},
Gender->{Female,Male},
HispanicOrigin->{Argentinean,Bolivian,CentralAmerican,Chilean,Colombian,CostaRican,Cuban,Dominican,Ecuadorian,Guatemalan,Hispanic,HispanicOrLatinoAllOther,Honduran,Mexican,Nicaraguan,NotHispanic,OtherCentralAmerican,OtherHispanicOrLatino,OtherSouthAmerican,Panamanian,Paraguayan,Peruvian,PuertoRican,Salvadoran,SouthAmerican,Spaniard,Spanish,SpanishAmerican,Uruguayan,Venezuelan},
MarginOfError->{MarginOfError,StandardError},
Percent->{Main},
Race->{AmericanIndian,Asian,Black,NativeHawaiian,Other,TwoOrMore,White,{All,Hispanic}},
TwoOrMore->{ThreeOrMore,TwoIncludingOther},
UrbanRural->{Rural,Urban}}
"Date"
is a qualifier. This post gives details on how to specify a "Date"
qualifier (156014); an area where the docs can improve.
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country", "Population", {"Date" -> DateObject[{2015}]}]
]
319,929,162 people
However, you do have a bit more flexibility with this syntax.
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country",
"Population", {"Date" -> Interval[{DateObject[{2015}], DateObject[{2019}]}]}]
]
and
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country", "Population", {"Date" -> All}]
]
Hope this helps.
$endgroup$
add a comment |
$begingroup$
You should report to WRI. As a workaround you may use the entity functions instead; it is a bit verbose.
First you can get a list of qualifier values of an EntityProperty
by
EntityValue[EntityProperty["Country", "Population"], "QualifierValues"]
{Age->{Adult,MiddleAge,PreSchool,SchoolAge,Senior,Young,YoungAdult},
CitizenshipStatus->{BornInPuertoRico,BornInUS,BornToAmericanParents,NaturalizedCitizen,NotCitizen,TotalCitizens},
Date->{},
Gender->{Female,Male},
HispanicOrigin->{Argentinean,Bolivian,CentralAmerican,Chilean,Colombian,CostaRican,Cuban,Dominican,Ecuadorian,Guatemalan,Hispanic,HispanicOrLatinoAllOther,Honduran,Mexican,Nicaraguan,NotHispanic,OtherCentralAmerican,OtherHispanicOrLatino,OtherSouthAmerican,Panamanian,Paraguayan,Peruvian,PuertoRican,Salvadoran,SouthAmerican,Spaniard,Spanish,SpanishAmerican,Uruguayan,Venezuelan},
MarginOfError->{MarginOfError,StandardError},
Percent->{Main},
Race->{AmericanIndian,Asian,Black,NativeHawaiian,Other,TwoOrMore,White,{All,Hispanic}},
TwoOrMore->{ThreeOrMore,TwoIncludingOther},
UrbanRural->{Rural,Urban}}
"Date"
is a qualifier. This post gives details on how to specify a "Date"
qualifier (156014); an area where the docs can improve.
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country", "Population", {"Date" -> DateObject[{2015}]}]
]
319,929,162 people
However, you do have a bit more flexibility with this syntax.
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country",
"Population", {"Date" -> Interval[{DateObject[{2015}], DateObject[{2019}]}]}]
]
and
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country", "Population", {"Date" -> All}]
]
Hope this helps.
$endgroup$
add a comment |
$begingroup$
You should report to WRI. As a workaround you may use the entity functions instead; it is a bit verbose.
First you can get a list of qualifier values of an EntityProperty
by
EntityValue[EntityProperty["Country", "Population"], "QualifierValues"]
{Age->{Adult,MiddleAge,PreSchool,SchoolAge,Senior,Young,YoungAdult},
CitizenshipStatus->{BornInPuertoRico,BornInUS,BornToAmericanParents,NaturalizedCitizen,NotCitizen,TotalCitizens},
Date->{},
Gender->{Female,Male},
HispanicOrigin->{Argentinean,Bolivian,CentralAmerican,Chilean,Colombian,CostaRican,Cuban,Dominican,Ecuadorian,Guatemalan,Hispanic,HispanicOrLatinoAllOther,Honduran,Mexican,Nicaraguan,NotHispanic,OtherCentralAmerican,OtherHispanicOrLatino,OtherSouthAmerican,Panamanian,Paraguayan,Peruvian,PuertoRican,Salvadoran,SouthAmerican,Spaniard,Spanish,SpanishAmerican,Uruguayan,Venezuelan},
MarginOfError->{MarginOfError,StandardError},
Percent->{Main},
Race->{AmericanIndian,Asian,Black,NativeHawaiian,Other,TwoOrMore,White,{All,Hispanic}},
TwoOrMore->{ThreeOrMore,TwoIncludingOther},
UrbanRural->{Rural,Urban}}
"Date"
is a qualifier. This post gives details on how to specify a "Date"
qualifier (156014); an area where the docs can improve.
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country", "Population", {"Date" -> DateObject[{2015}]}]
]
319,929,162 people
However, you do have a bit more flexibility with this syntax.
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country",
"Population", {"Date" -> Interval[{DateObject[{2015}], DateObject[{2019}]}]}]
]
and
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country", "Population", {"Date" -> All}]
]
Hope this helps.
$endgroup$
You should report to WRI. As a workaround you may use the entity functions instead; it is a bit verbose.
First you can get a list of qualifier values of an EntityProperty
by
EntityValue[EntityProperty["Country", "Population"], "QualifierValues"]
{Age->{Adult,MiddleAge,PreSchool,SchoolAge,Senior,Young,YoungAdult},
CitizenshipStatus->{BornInPuertoRico,BornInUS,BornToAmericanParents,NaturalizedCitizen,NotCitizen,TotalCitizens},
Date->{},
Gender->{Female,Male},
HispanicOrigin->{Argentinean,Bolivian,CentralAmerican,Chilean,Colombian,CostaRican,Cuban,Dominican,Ecuadorian,Guatemalan,Hispanic,HispanicOrLatinoAllOther,Honduran,Mexican,Nicaraguan,NotHispanic,OtherCentralAmerican,OtherHispanicOrLatino,OtherSouthAmerican,Panamanian,Paraguayan,Peruvian,PuertoRican,Salvadoran,SouthAmerican,Spaniard,Spanish,SpanishAmerican,Uruguayan,Venezuelan},
MarginOfError->{MarginOfError,StandardError},
Percent->{Main},
Race->{AmericanIndian,Asian,Black,NativeHawaiian,Other,TwoOrMore,White,{All,Hispanic}},
TwoOrMore->{ThreeOrMore,TwoIncludingOther},
UrbanRural->{Rural,Urban}}
"Date"
is a qualifier. This post gives details on how to specify a "Date"
qualifier (156014); an area where the docs can improve.
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country", "Population", {"Date" -> DateObject[{2015}]}]
]
319,929,162 people
However, you do have a bit more flexibility with this syntax.
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country",
"Population", {"Date" -> Interval[{DateObject[{2015}], DateObject[{2019}]}]}]
]
and
EntityValue[
Entity["Country", "UnitedStates"],
EntityProperty["Country", "Population", {"Date" -> All}]
]
Hope this helps.
edited 1 hour ago
answered 2 hours ago
EdmundEdmund
26.2k330100
26.2k330100
add a comment |
add a comment |
user10311334 is a new contributor. Be nice, and check out our Code of Conduct.
user10311334 is a new contributor. Be nice, and check out our Code of Conduct.
user10311334 is a new contributor. Be nice, and check out our Code of Conduct.
user10311334 is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Both statistics and its implementation in Mathematica are slow. Lags usually equal few years. WolframAlpha in my Mma through ==Population of United States in 2015 answers 320 million people (2015 estimate).
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– user64494
3 hours ago
1
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Also WA in my Mma answers 327 million people (world rank: 3^(rd)) (2018 estimate)
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– user64494
2 hours ago
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@user64494 That is interesting,
WolframAlpha[ "Population of the United States"]
for me returns 324 million people (2017 estimate). Seems like there are different data bases queried?$endgroup$
– gwr
2 hours ago
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@gwr: Your question should be addressed to Wolfram developers, not to me. Try WolframAlpha["Population of the United States in 2018"]. Good luck!
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– user64494
2 hours ago
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@user64494 But you indeed have given the answer! Specifically asking for the population in 2018 will give the value you have given. It simply will not appear just asking for population for some reason. :)
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– gwr
2 hours ago